Mth101 first assignment spring 2011 solution

[ikashif]

Xà-5 x^3+2x^2-15x


=lim |x+5|
xà-5 x(x+5)(x-3) X^3+2x^2-15


NOW
x+5 if x>-5
|x+5|= -(x+5) if x<-5
0 if x=-5
Left Hand Limit

Lim _ |x+5|
xà-5 x(x+5)(x-3)

=lim _ -(x+5)
xà-5 x(x+5)(x-3)
=lim _ -1
xà-5 x(x-3)

= -1 = -1
-5(-5-3) -5(-8)

= -1
40
Right Hand Side

Lim |x+5|
xà-5^+ x(x+5)(x-3)

=lim
xà-5^+ x+5 = 1
x(x+5)(x-3) 40
NOW
Left Hand Side # Right Hand Side
LIMIT DOES NOT EXIST AT X= -5

[ikashif]

U people need to concentrate a little to understand ...

[moon13]

please jaldi karian please

[Xpert]

kia jaldi karna hai????? ek bonus day bhi hota hai janab.

[Vuhelper]

assignment on attachment

[sana.pari]

Question # 2
4x2+4y2+16y-4x=19
4x2+4y2+2(-2)x+2(4y)-19=0
g = -2
f = +8 c = -19
r = f 2 + g2 − c
= (−2)2 + 82 − (−19)
= 4 + 64 + 19
= 87
Radius = 87
Center = (-2, 8)

Question # 3
x ≥ −2
8 − x
⇒ x ≥ −2 ( 8 − x )
⇒ x ≥ −16 + 2 x
⇒ x − 2 x ≥ −16
⇒ − x ≥ −16
⇒ x ≤ 16
⇒ { x x ∈ R x ≤ 16}

[nsdaud]

plz upload it in word or pdf file it is very dificult to unerstand the words.

plz today is last date of this assignment

[Xpert]

oh ho. ok let me do something for you . i guess you still have a bonus day...

[nsdaud]

plz upload question NO.1
plz hurry up