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STA301 Assignment No.3 Fall January 2011-2012
#1
[B]Assignment No.3 (Course STA301)

Fall 2011 (Total Marks 30)

Deadline

Your Assignment must be uploaded/ submitted before or on

23:59 January 04, 2012

(STUDENTS ARE STRICTLY DIRECTED TO SUBMIT THEIR ASSIGNMENT BEFORE OR BY DUE DATE. NO ASSIGNMNENT AFTER DUE DATE WILL BE ACCEPTED VIA E.MAIL).

Rules for Marking

It should be clear that your Assignment will not get any credit IF:

The Assignment submitted, via email, after due date.
The submitted Assignment is not found as MS Word document file.
There will be unnecessary, extra or irrelevant material.
The Statistical notations/symbols are not well-written i.e., without using MathType software.
The Assignment will be copied from handouts, internet or from any other student’s file. Copied material (from handouts, any book or by any website) will be awarded ZERO MARKS. It is PLAGIARISM and an Academic Crime.
The medium of the course is English. VU solutions.com Assignment in Urdu or Roman languages will not be accepted.
Assignment means Comprehensive yet precise accurate details about the given topic quoting different sources (books/articles/websites etc.). Do not rely only on handouts. You can take data/information from different authentic sources (like books, magazines, website etc) BUT express/organize all the collected material in YOUR OWN WORDS. Only then you will get good marks.


Objective(s) of this Assignment:

The assignment is being uploaded to build up the concepts about probability distributions and approximation normal to binomial.
Properties of expectations.
Application of joint probability distribution and how to judge dependent and independent variables.
How to solve integration and the concept of distribution function.
Assignment No.3 (Lessons 23-30)

Question 1: Marks: 8+2=10

a) Flaws in a certain type of drapery material appear on the average of three in 250 square feet. If we assume the Poisson distribution, find the probability of at vu solutions.com most one flaw in 450 Square feet.

b) What is the mean and variance for the given Poisson distribution of a random variable X;

Question 2: Marks: 6+4=10

a) For the following probability distribution;

Show that E (5X+3) = 5E(X) + 3

X P(X)
0
1

20.3

0.6

0.1

b) Find the distribution function for the following density function.

Question 3: Marks: 5+5=10

Let X and Y have the joint probability distribution described as follows,

X
Y1 2 31



2



31/12 1/6 0



0 1/9 1/5



1/18 1/4 2/15

Find the two marginal probability distribution for X and Y.


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