Why we write main rgc,char**argv in C++ 2012

[Vuhelper]

Why we write main(argc,char**argv) what is its use ?when we use it and what is its meaning? please explain it with some example

C and C++ have a special argument list for main( ), which looks like this:

int main(int argc, char* argv[]) { // ...

The first argument is the number of elements in the array, which is the second argument. The second argument is always an array of char*, because the arguments are passed from the command line as character arrays (and remember, an array can be passed only as a pointer). Each whitespace-delimited cluster of characters on the command line is turned into a separate array argument. The following program prints out all its command-line arguments by stepping through the array:

Example:

int main(int argc, char* argv[]) {

cout << "argc = " << argc << endl;

for(int i = 0; i < argc; i++)

cout << "argv[" << i << "] = "

<< argv[i] << endl;

}

You’ll notice that argv[0] is the path and name of the program itself. This allows the program to discover information about itself. It also adds one more to the array of program arguments, so a common error when fetching command-line arguments is to grab argv[0] when you want argv[1].

You are not forced to use argc and argv as identifiers in main( ); those identifiers are only conventions (but it will confuse people if you don’t use them). Also, there is an alternate way to declare argv:

int main(int argc, char** argv) { // ...

Both forms are equivalent