CS502 Assignment Solution Required!!!!!!!!

[Zeshan Awan]

Plz any one can send the solution of Cs502 . Today is extended day .........

[Xpert]

Code:

[COLOR=#000000][FONT=Times New Roman][FONT=arial][FONT=Arial][SIZE=3] Question # 1 Solution[/SIZE][/FONT] [FONT=Arial][SIZE=3]y=0; //Initialize y=0[/SIZE][/FONT] [FONT=Arial][SIZE=3]x=0; //Initialize x=0[/SIZE][/FONT] [FONT=Arial][SIZE=3]for (i=n; i>0;i=i-1) // This loop will run approximately [B]n [/B]times[/SIZE][/FONT] [FONT=Arial][SIZE=3]{ y=y+1;} // The loop will run approximately [B]n [/B]times and add the value of 1 in y.[/SIZE][/FONT] [FONT=Arial][SIZE=3]for (i=1;i<=n;i=i*3) //This statement will run approximately [B]2n-1 [/B]times.[/SIZE][/FONT] [FONT=Arial][SIZE=3]{ //First loop Start[/SIZE][/FONT] [FONT=Arial][SIZE=3]for (j=1;j<=3n;++j) // In the nested loop, The variable j depends upon the value of 3n.[/SIZE][/FONT] [FONT=Arial][SIZE=3]{ //Second loop Start[/SIZE][/FONT] [FONT=Arial][SIZE=3]for(k=0;k<n; k=k+5) //In the nested loop again, The statement will run n/5 times[/SIZE][/FONT] [FONT=Arial][SIZE=3]{ //Third loop Start[/SIZE][/FONT] [FONT=Arial][SIZE=3]x=x+5; // The statement add 5 in the X variable.[/SIZE][/FONT] [FONT=Arial][SIZE=3]} //Third loop close[/SIZE][/FONT] [FONT=Arial][SIZE=3]} //Second loop close[/SIZE][/FONT] [FONT=Arial]} //First loop close[/FONT][/FONT][/FONT][/COLOR]

[Zeshan Awan]

Bundle of Thanx

[Xpert]

welcome....