04-19-2011, 02:28 AM
acha ab roaz ludiyan nahi dalni chaheya.
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Mth101
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04-19-2011, 02:28 AM
acha ab roaz ludiyan nahi dalni chaheya.
04-26-2011, 12:20 AM
assignment no. 2 ka solution kab aye ga??
04-26-2011, 04:33 AM
jald hi ah raha hai only on vuhelp.net
04-26-2011, 09:13 AM
ab tuk to nahi aya Last Hour main ayegha
04-26-2011, 06:40 PM
may be not a big deal
04-27-2011, 01:29 AM
any body send me the solution for mth 202 assignment # 2 today is last date
04-27-2011, 03:30 AM
where is the assignment?
04-27-2011, 05:24 PM
have u did it ?
dan where is it ?
04-27-2011, 05:28 PM
Question 01:-
Check whether or not the function is continuous at . Solution: f (x) = c (x2 -9)/x+3 = -3 (x+3)(x-3)/(x+3) =-3 x-3 = -3 x = 3-3 = 0 x = 0 f(0) = (0-9)/ (0+3) = -3 = c Hence Its Contineous function Question 02:- For a function , find the instantaneous rate of change of g(x) with respect to x at a general point . Solution: Suppose: At x0 x = 0 g(0) = (5-0) / (3+0) = 5/3 = 1.6 is rate of change Question 03:- By using ( ) definition of the limit of a function, evaluate ‘ ’ corresponding to if , . Solution: (x2 – 1) / (x + 1) (x + 1)(x – 1) / (x + 1) (x – 1) -1 - 1 = -2 Limit Exist |
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